Haha, whoops. Forgot to square a number properly when I was doing my math. I used the V2^2 = Vi + 2ad formula and you can probably see where I messed it up. Thanks for correcting it though.

ah, yeah, gotta watch out for those squares

Anonymous

Anonymous asked:

Fun fact about Yang getting hit: assuming that Yang spent equal times falling as she did ascending, and Remnant's gravity is similar to Earth's; Nora hit Yang approximately 2.275 kilometers into the air (does not account for wind resistance).

Did you include her changing velocity as she went skyward? Because I’m sure it’s much shorter than that.

ok, bout to get real nerdy here. so we’ll stick with the assumption that the ascent and descent take the same amount of time. therefore it took yang 46 seconds to reach her maximum height. we’ll also neglect air resistance and assume no lateral motion (thought that doesn’t really matter much anyway). we know that at that max height, her velocity is 0 m/s. we don’t know what her initial velocity is, but if we assume gravity equal to earth’s (9.8 m/s/s down), we can find that out.

v2-v1 = a*t.

0-v1 = -9.8*46.

turns out, yang’s initial upward velocity was 450.8 m/s (which is just over 1000 miles per hour). now to find the height.

h = v1*t - 0.5*a*t*t

h = 450.8*46 - 0.5*9.8*46*46

the math comes out to 10,368 meters. that’s just under 6.5 miles.

so itl;dr don’t fuck with nora.

tali voice: NERRRRRRD

hey, i warned ya :P go use your emergency induction port

Anonymous

Anonymous asked:

Fun fact about Yang getting hit: assuming that Yang spent equal times falling as she did ascending, and Remnant's gravity is similar to Earth's; Nora hit Yang approximately 2.275 kilometers into the air (does not account for wind resistance).

Did you include her changing velocity as she went skyward? Because I’m sure it’s much shorter than that.

ok, bout to get real nerdy here. so we’ll stick with the assumption that the ascent and descent take the same amount of time. therefore it took yang 46 seconds to reach her maximum height. we’ll also neglect air resistance and assume no lateral motion (thought that doesn’t really matter much anyway). we know that at that max height, her velocity is 0 m/s. we don’t know what her initial velocity is, but if we assume gravity equal to earth’s (9.8 m/s/s down), we can find that out.

v2-v1 = a*t.

0-v1 = -9.8*46.

turns out, yang’s initial upward velocity was 450.8 m/s (which is just over 1000 miles per hour). now to find the height.

h = v1*t - 0.5*a*t*t

h = 450.8*46 - 0.5*9.8*46*46

the math comes out to 10,368 meters. that’s just under 6.5 miles.